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So area = (\frac3\sqrt34 (16^2/3)). (16^2/3 = (2^4)^2/3 = 2^8/3 = 4 \cdot 2^2/3 = 4\sqrt[3]4).
For now, here’s a in the style of MJC 2010 H2 Math Prelim Paper 1: Question (Complex Numbers) Mjc 2010 H2 Math Prelim
The complex number (z) satisfies the equation [ z^3 = -8\sqrt2 + 8\sqrt2 i. ] So area = (\frac3\sqrt34 (16^2/3))
I notice you’ve asked for "Mjc 2010 H2 Math Prelim" — but it seems you want me to , likely meaning a problem or solution from that paper . Mjc 2010 H2 Math Prelim