Hdmovies4u.rsvp-wild.wild.punjab.2024.webrip.72... šÆ Instant
If you want to based on that pattern or filename, hereās what I can help with, depending on what exactly you mean by āgenerate featureā: 1. Extract Movie Metadata Feature (Python example) import re filename = "HDMovies4u.Rsvp-Wild.Wild.Punjab.2024.WebRip.72..."
pattern = r'(?P<source>[^.]+).(?P<group>[^.]+)-(?P<movie>.+?).(?P<year>\d{4}).(?P<quality>WebRip).(?P<resolution>\d{2,3})' match = re.search(pattern, filename, re.IGNORECASE) HDMovies4u.Rsvp-Wild.Wild.Punjab.2024.WebRip.72...
if match: print(match.groupdict())